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Concept — what does that mean?

Quadratic functions

A function with an x² term, f(x) = ax² + bx + c, whose graph is a parabola. f(x) = x² − 4x + 3 is a quadratic function, but f(x) = 2x + 1 is not.

In Swedish: Andragradsfunktion

What it is

A quadratic function is a function f(x) = ax² + bx + c, where a, b and c are fixed numbers and a ≠ 0. Its graph is a parabola. With a = 0 the x² term disappears and what is left is a linear function; that is why the definition requires a ≠ 0.

The three numbers steer the parabola in different ways:

Three properties are asked about most: the axis of symmetry, the vertex and the zeros. Take f(x) = x² − 4x + 3, with a = 1, b = −4 and c = 3.

With a < 0 everything turns over: f(x) = −x² + 6x − 5 has the highest point (3, 4) and the zeros 1 and 5.

The same function can be written in three ways, and each one shows something:

The number of zeros is two, one or none, and the discriminant decides which. f(x) = x² − 4x + 3 has two. f(x) = x² has one, x = 0, because the lowest point lies on the x-axis. f(x) = x² + 1 has none, because the lowest point (0, 1) lies above the x-axis.

Not quadratic functions:

Why it matters

Quadratic functions appear wherever something has a largest or smallest value. Without air resistance and with g ≈ 10 m/s², the height of a ball thrown straight up at 20 m/s is h(t) = −5t² + 20t metres after t seconds. The axis of symmetry t = −20/(2 · (−5)) = 2 gives the greatest height h(2) = −20 + 40 = 20 m, and the zeros t = 0 and t = 4 are the throw and the landing. A rectangle with perimeter 20 has sides x and 10 − x and area A(x) = x(10 − x) = −x² + 10x, which is largest, 25, when x = 5.

Which tool fits depends on the question:

Change a, b and c with the sliders in the graphing calculator and watch the parabola turn, widen and move.

Common misconceptions

Common questions

What is the difference between a quadratic function and a quadratic equation? The function f(x) = x² − 4x + 3 is a rule that gives a y for each x. The equation x² − 4x + 3 = 0 asks which x give y = 0, and the answer is x = 1 and x = 3.

How do I find the vertex without differentiating? Work out x = −b/(2a) and substitute it into the function to get y. The derivative gives the same x: f′(x) = 2ax + b is 0 at x = −b/(2a).

Is the vertex a maximum or a minimum? The sign of a decides. When a > 0 the parabola opens upwards and the vertex is a minimum. When a < 0 it is a maximum.

How many points does it take to fix a quadratic function? Three points with different x-values that do not lie on one straight line. The points (0, 3), (1, 0) and (2, −1) give c = 3, a + b = −3 and 4a + 2b = −4. That is a system of linear equations with the solution a = 1 and b = −4, so f(x) = x² − 4x + 3.

Last reviewed October 22, 2026 ·How pages are reviewed

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